ln ∆ABC and ∆PQR, ∠ A =∠ P, ∠C= ∠ R and AB = PQ.
Prove that ∆ABC ≈APQR.
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Answered by
10
Given :
∠A= ∠P
∠C= ∠R
AB= PQ
To prove:
∆ABC≅∆PQR
Proof:
In ∆ABC & ∆PQR
∠A= ∠P ( Given)
∠C= ∠R ( Given)
AB= PQ ( Given)
∆ABC≅∆PQR (by ASA Congruence rule)
==================================================================================
Hope this will help you....
∠A= ∠P
∠C= ∠R
AB= PQ
To prove:
∆ABC≅∆PQR
Proof:
In ∆ABC & ∆PQR
∠A= ∠P ( Given)
∠C= ∠R ( Given)
AB= PQ ( Given)
∆ABC≅∆PQR (by ASA Congruence rule)
==================================================================================
Hope this will help you....
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Answered by
4
< A = < P (given)
< C = < R (given)
AB = PQ (given)
So, according to Angle Side Angle (ASA) property it is proved.
Hence, triangle ABC is congruent to triangle PQR.
Hope it helps you.
With regards@
Tanisha
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