Question

ln fig.9.26,DE=DFand D=50°.find angle a,band c

Answer 1

Hola ^_^

Here is your answer

In Triangle DEF
DE=DF
So it as isosceles triangle.

Therefore,
Angle E = Angle F

【Isosceles thereom】


So angle D = 50°

By angle sum property of a triangle

D +E + F =180°

50° + x + x= 180°
2x= 180 - 50
2x= 130

so x= 130/2
x= 65

So Angle E= F= 65°

Hope it helps !!

Answer 2

$\huge \underline{solution}....$

Given that , DE=DF ( therefore it is a isoceles triangle)


D= 50 degree (given)

D+E+F = 180 (Sum of a tri. is 180 degree)

50 + x + x = 180 .

2 x = 180 -50

2x = 130

x = 130/2 = 65.

So the E=65 degree = F .

'Since it is isocles triangle there E=F'

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Or a=b =65 degree,
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$\bold{hope \: it \: will \: helps \: ya..}$