ln fig, APB and AQP are semi-circles, and, AO = OB. If the perimeter of the figure is 47 cm, find the area of the shaded region. (Use π = 22/7)
Attachments:
Answers
Answered by
4
Answer:
your answer are in pic above
Attachments:
Answered by
8
Question :
• ln fig, APB and AQP are semi-circles, and, AO = OB. If the perimeter of the figure is 47 cm, find the area of the shaded region. (Use π = 22/7).
Given :
• APB and AQP are semi curcles.
• Perimeter of the figure = 47 cm.
To find :
• Find the area of a shaded region.
Solution :
★ Area of tthe shaded region ★
⇒Area = area of the circle - 1/4 area of the circle
⇒Area = 1 - 1/4 area of the circle [ we used 1 because the fraction of the circle is equal to 1; 4/4 = 1]
⇒Area = 3/4 area of the circle
⇒Area = 3/4 × πr²
⇒Area = 3/4 × 22/7 × 7²
⇒Area = 3/4 × 22/7 × 7 × 7
⇒Area = 3/4 × 22 × 7
⇒ Area = 3/2 × 11 × 7
⇒Area = 3/2 × 77
⇒Area = 231/2
⇒Area = 115.5 cm.
Therefore, the area of the shaded region is 115.5 cm.
_____________________
Joyful learning!!!⛅
Similar questions