ln fig. DE||BC. lf AD = x, DB = x-3, AE = x+3 and EC= x-2, find the value x.
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can u tell how is the figure n triangle or quadilateral
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Triangle ABA, DE||BC, so by Basic Proportionality theorem, AD /DB = AE /EC
substituting the values, we get,
x/x-2 =x+2/x-1
By cross multiplying, we get,
x(x-1) =(x+2)(x-2)
x2 -x = x2 -4
x=4
Step-by-step explanation:
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