Question

LN is the diameter of a circle with centre M(4, 0). If the coordinates of the points L and N are (2, 3) and (6, a) respectively, find the value of a.

Answer 1

Step-by-step explanation:

Now, M(4, 0), L(2, 3), N(6, a)

So, LN is the diameter and M is the centre of the circle

Since LN passes through M, and divides into radii, we can say ML = MN

Using the distance formula:

$D = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{2})^2 }$

So,

$D_{ML} = \sqrt{( 2-4)^2 + (3-0)^2 } = D_{MN} = \sqrt{(6-2)^2 + (a-3)^2 }$

Thus, after removing the square roots and squaring the numbers, you can obtain your answer!