Question

ln(sin^2x)
find the derivatives
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Answer 1

welcome to the concept of derivative ♣️

formulas used

d(ln X)/ dx = 1/X

d(x^n )/dx = nx^n-1

d( sinx)/dx = cosx

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Answer 2

$y = ln( \sin {}^{2} (x) )$

$\frac{dy}{dx} = \frac{1}{ \sin {}^{2} (x) } \times 2 \sin(x) \times \cos(x)$

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