Question

Ln( t^2 +t) differentiate

Answer 1

Step-by-step explanation:

$\tt\implies \tt \ln( {t}^{2} + t)$

$\tt\implies \dfrac{ d}{dt} \ln( {t}^{2} + t)$

$\tt\implies \dfrac{1}{ {t}^{2} + t } \cdot2t + 1$

$\tt\implies \dfrac{2t + 1}{ {t}^{2} + t }$

$\tt\implies \dfrac{2}{t} + \dfrac{1}{t}$