ln the above example, assuming that the bench on which Mahendra is sitting is frictionless, starting with zero velocity, what will be Mahendra's velocity of motion towards Virat after 1 s ? Will this velocity change with time and how?
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Answer:
F = 4.002 X 10^-7 N,
m=75Kg.
Solution: According to Newton's 2nd law of motion,
F=ma
a=F/m
=4.002 X 10^-7/75
=4002 X 10^-10/75
=53.36 X 10^-10 (dividing 4002 by 75)
= 53.4 X 10^-10 (round up .36 as .4)
= 5.34 X 10^-9 m/s^2.
According to newton's 1st equation of motion,
V=U+at.
=0 + 5.34 X 10^-9 X 1
= 5.34 X 10^-9 m/s.
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