ln the figure below OAB is a flower bed in the shaoe of sector of a circle pf radius 40mand angle AOB : 60'. Also a 15m wide track is made . Flower bed is made at the rate of Rs.
3.60 per m²and the rate of making concrete track is Rs. 50 per m². Find the total amount
spent. (Take π:3.14)
Answers
Answer:
you should increase point
Given : ln the figure below OAB is a flower bed in the shape of sector of a circle of radius 40 m and angle AOB : 60°.
Also a 15m wide track is made .
Flower bed is made at the rate of Rs. 3.60 per m² and the rate of making concrete track is Rs. 50 per m².
To Find : the total amount spent. (Take π:3.14)
Solution:
Flower bed is a sector with angle 60° and radius = 40 m
Area of Flower bed = (60/360) πr²
= (1/6) (3.14) (40)²
= 2512/3 m²
Flower bed is made at the rate of Rs. 3.60 per m²
Cost of Flower bed = 3.60 * 2512/3
= 3,014.4 Rs
Area of Track = ((360-60)/360) ( π(40)² - π(40 - 15)²)
= (300/360) (3.14) (40² - 25²)
= (5/6)(3.14)65 * 15
= 1.57 * 65 * 25
= 2,551.25 m²
rate of making concrete track is Rs. 50 per m²
Cots of concrete track = 50 * 2,551.25 = 1,27,562.5 Rs
Total cost = 1,27,562.5 + 3,014.4
= 1,30,576.9 Rs
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