Question

ln the given figure, ABC is a triangle in which angle BAC =30.show that BC is equal to the radius of the circimcircle of triangle ABC, whose centre is O.​

Answer 1

Answer:

the given figure, ΔABC is a right angled triangle in which ∠ A = 90°. Semicircles are drawn on AB, AC and BC. In the given figure, ΔABC is a right angled triangle in which ∠ A = 90°. Semicircles are drawn on AB, AC and BC as diameters.04-Oct-2018

Answer 2

The angle subtended by a chord at center is double the angle subtended by it on any other point on the major segment of circle.

So ∠BOC=60°

ΔBOC

OB=OC

The sides are equal and included angle is 60°

So the triangle is eqquilateral

Hence BC=OB(radius)