Question

ln the given figure, show that PQ = AB, where PQ and AB are common tangents.​

Answer 1

Answer:

PQ=AB

Step-by-step explanation:

Let the intersection point be O,

Thus, PO=OB-------- (1)

and, OQ=OA---------(2)

adding equation (1) and (2), we get,

OP+OQ=OA+OB

Hence, PQ=AB

Answer 2

Step-by-step explanation:

let the intersection point of AB and PQ

be O

OP=OB tangent of the same circle. eq1

OQ=OA tangent of the same circle. eq2

adding eq1 and eq2

we get

PQ=AB

hence proved