Question

LNCR
ODE
11.
The reverse bias in a junction diode is changed from
5V to 15V then the value of current changes from
38uA to 88uA. The resistance of junction diode will be
2)3 x 10502
4)102
1)4, 10502
3) 2 x 0522
12
diagram is​

Answer 1

Answer:

×105Ω

3×105Ω

2×105Ω

106Ω

Answer :

C

Solution :

R=ΔVΔI=15−5(88−38)×10−6=1050×10−6

=1065=105×105=2×105Ω.

Explanation:

mark me as brainliest

Answer 2

Answer:

3) 2×105ohm

Explanation:

3) 2×105ohm