Question

Lo
19.0 is the centre of a circle. If ZAOB = =100° and
ZAOC = 90°, then <BAC =
85
80
90
75​

Answer 1

Answer:

O is the centre of a circle. If ZAOB = =100° and ZAOC = 90°, then <BAC

$\\ \frac{180 - 100}{2} + \frac{180 - 90}{2} \\ \\ = \frac{80}{2} + \frac{90}{2} \\ \\ = 40 + 45 = 85$