Question

? lo
An electron in an atom is revolving around
the nucleus in a circular orbit of radius
2 12.6 Ao with a speed of
loog X 10omis
calculate the resultant orbital magnetic
dipole moment of electron bio
1.68 10-19
С. me: 9.1X10-31 kg)​

Answer 1

Explanation:

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Answer 2

Answer:

$Given, frequency ie; angular velocity v= 6.8×109MHz</p><p></p><p>Current due to revolving electron I=2πrev------- (1),</p><p></p><p> where r= orbital radius.</p><p></p><p>Area of the orbit, A=πr2</p><p></p><p>  A=3.14×(0.53×10−10)2m2</p><p></p><p>   =8.8247×10−21m2</p><p></p><p>magnetic moment</p><p></p><p>M=IA-------- (2)</p><p></p><p>From (1), I=2πrev=2×π×0.53×10−101.6×10−19×6.8×109</p><p></p><p>   = 3.267 A</p><p></p><p>(2) =>M=IA= 3.267×8.824×10−21</p><p></p><p>  M= 2.882×10−20 Amp.m2</p><p></p><p>$

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