Question

Load=1000N
Effort=300N
Load distance=5m
effort distance=20cm
find MA, VR, Efficiency

Answer 1

Answer:

Explanation:

Load =1000N

Effort = 300N

Load distance (L.d) = 5 m

Effort distance (E.d) = 20m

Now,

M.A = load / effort=1000 / 300=3.33

V.R = effort distance / load distance = 20 / 5 = 4

Efficiency    =M.A / V.R * 100%   = 3.33/ 4∗100%     = 0.83 %

Answer 2

Answer:

If Load=1000N

, Effort=300N

, Load distance=5m

, effort distance=20cm

Mechanical advantage = $\frac{10}{3}$

Velocity ratio = $0.04$

Efficiency  = $83\%$

Explanation:

• The mechanical advantage, velocity ratio, and efficiency of a lever can be expressed as,

        $\text{ { Mechanical\ advantage }(M . A)}=\frac{\text { Load }}{\text { Effort }} = \frac{L}{E}$    ...(1)

        $\text { Velocity ratio }(\text { V.R })=\frac{E_{d}}{L_{d}}$         ...(2)

        $\text { Efficiency}\ (\eta) = \frac{\text { M.A }}{\text { V.R } }$                  ...(3)

Where,

   L   -    Load

   E   -   Effort

   $L_d$  -   Load distance

   $E_d$  -   Effort distance

In the question, it is given that,

$L = 1000\ N$                   $E = 300\ N$            

$L_d = 5.0\ m$                    $E_d = 20\ cm = 0.20\ m$  

M.A can be obtained by substituting these values into equation (1)

$\text M \cdot \text A=\frac{1000}{300}=\frac{10}{3}$

V.R  can be obtained by substituting the values of $E_d$ and $L_d$ into equation (2)

$\text V \cdot \text R =\frac{0.20}{5}=0.04$

Efficiency,

$\eta = \frac{\frac{10}{3} }{0.04} \times 100 = 83 \%$