Chemistry, asked by gudiyaofficial234, 1 year ago

Lobery-di-Bruyn-van-Ekenstein's rearrangement

Answers

Answered by sivachidambaramthang
3

In carbohydrate chemistry, the Lobry de Bruyn–van Ekenstein transformation also known as the Lobry de Bruyn–Alberda–van Ekenstein transformation is the base or acid catalyzed transformation of an aldose into the ketose isomer or vice versa, with a tautomeric enediol as reaction intermediate. Ketoses may be transformed into 3-ketoses, etcetera. The enediol is also an intermediate for the epimerization of an aldose or ketose. [1] [2]

The reactions are usually base catalyzed, but can also take place under acid or neutral conditions.[1] A typical rearrangement reaction is that between the aldose glyceraldehyde and the ketose dihydroxyacetone in a chemical equilibrium.

The Lobry de Bruyn–van Ekenstein transformation is relevant for the industrial production of certain ketoses and was discovered in 1885 by Cornelis Adriaan Lobry van Troostenburg de Bruyn and Willem Alberda van Ekenstein.

Answered by ansiyamundol2
0

Answer:

Lobery-di-Bruyn-van-Ekenstein's rearrangement :

The Lobry de Bruyn–Van Ekenstein transformation is a base or acid catalysed transformation of an aldose into the ketose isomer, or vice versa, using a tautomeric enediol as a reaction intermediate in carbohydrate chemistry.

Explanation:

Ketoses can be converted into 3-ketoses, and so on. The enediol is also a step in the process of epimerizing an aldose or ketose.

The reactions are commonly catalysed by a base, but they can also happen in an acidic or neutral environment.

In a chemical equilibrium, the aldose glyceraldehyde and the ketose dihydroxyacetone undergo a classic rearrangement reaction.

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