Question

locate √10, -√10 on number line​

Answer 1

Step-by-step explanation:

Draw a number line and point numbers in both + and - sides. Go to +3 point draw a line of 1 units perpendicular to it. Now draw a line from 0 to the perpendicular line's vertex. The length of this line is √10 place it in both - and + sides. the point placed in - side is -√10

proof:

$\sqrt{ {3}^{2} + {1}^{2} } \\ = \sqrt{9 + 1} \\ = \sqrt{10} \: units$

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