Locate √10 and √17 on the number line.
Answers
Answer:
Presentation of
10
on the number line:
We write 10 as the sun of the square of two natural numbers:
10=1+9=1
2
+3
2
On the number line, taken OA=3 units.
Draw BA=1 unit, perpendicular to OA, Join OB.
By Phythagoras theorem, OB=
10
Using a compass with centre O and radius OB, draw an arc which intersects the number line at the point C. Then, C corresponds to
10
.
Presentation of
17
on the number line:
We write 17 as the sum of the square of two natural numbers.
17=1+16=1
2
+4
2
On the number line, take OA=4 units.
Draw BA=1 units, perpendicular to OA. Join OB.
By Pythagoras theorem, OB=
17
Using a compass with centre O and radius OB, draw an arc which intersects the number line at the point C. Then, C corresponds to
17
.
Answer:
√10
Take a line segment AO=3 unit on the x-axis. ( ...
Draw a perpendicular on O and draw a line OC=1 unit.
Now join AC with 10 .
Take A as center and AC as radius, draw an arc which cuts the x-axis at point E.
The line segment AC in the below diagram represents 10 units
√17
Now construct AB of unit length perpendicular to Oa . Then taking O as centre and OB as radius. Draw an arc intersecting number line at C . C is represented as √17.