Locate 2+root3 on a number line
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First draw a right angle triangle with base 1 and hight 1. So you got hypotenuse=√(1²+1²)=√(2) ..
Now use this √(2) length (use geometric compass) and draw a new right angle triangle with base 1 and height √(2). So now your hypotenuse of the new right angle triangle is =√(1²+(√(2))²)= √(1+2) =√(3)..
So now you have √(3) length.. You have to represent 2+√(3) in number line. So first mark 2 in number line and then from 2 use geometric compass and make a circle with the same length of √(3) as radious in number line. So between 1 and 2 where the circle cuts that is 2-√(3) and between 2 and 3 where the circle cuts that is your 2+√(3)…
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hope it's help you
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