locate √3 on the number line.
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24
Draw a line. At a point A on the line construct a line which is perpendicular to the first line. Mark a point C on this line a distance of one unit from A.
Using the compass, draw an arc of a circle with radius 2 and center C so that the arc intersects the first line at B. Draw the line segment CB.
Now you have a right triangle with hypotenuse of length 2 units and one side of length 1 unit. Hence, by Pythagoras' Theorem
|CA| 2 + |AB| 2 = |BC| 2
That is
1 + |AB| 2 = 4
and thus |AB| 2 = 3 and |AB| is the square root of 3. Hope I helped u... Plzz mark as the BRAINLIEST answer..
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we know that , √1 =1 and √4 =2
√3 lies between √1 and √4
√3 lies between 1 and 2
process:
1) draw x - axis
2) mark 0cm - 5cm
3) locate √3 somewhere between 1 cm and 2cm.
√3 lies between √1 and √4
√3 lies between 1 and 2
process:
1) draw x - axis
2) mark 0cm - 5cm
3) locate √3 somewhere between 1 cm and 2cm.
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