locate√3on number line
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First draw a number line having points (at least) [0,3]. If we denote the point 0 as “O” and point 1 as “A” then OA will be equal to 1 unit. Then at point A draw a perpendicular of length AB=1 unit ( equal to the distance from 0 to 1 in the number line i.e. OA). And join the points O and A, so that OAB is a right angled triangle. Then by pythagoras theorem,
OB^2=OA^2+AB^2
=> OB=sqrt (1^2+1^2)
=>OB = root2
Now, again draw a perpendicular at point B of length BC= 1 unit and join the points O and C. Again by pythagoras theorem we get OC = root 3. Then by compus taking radius =OC, draw an arc so that it cuts the number line at D. Then the distance OD will be the square root of 3.
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Answer:
Step-by-step explanation:
steps of construction :-
Step 1. Take 1 unit from “0” and draw a perpendicular at that point.
Step 2. Join line ie., hypotenuse
Step 3. Keep compass point on “0” and pencil point on top of triangle and draw an arc.
Step 4. The point obtained is √2
Step 5. Now draw 1 unit perpendicular at √2 and similarly draw hypotenuse.
Step 6. Similarly draw an arc as we did in √2 case and point obtained on number line is √3.
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