Locate √6,√10,√17 on the number line
Answers
Answer:
hii
Step-by-step explanation:
Presentation of
5
on number line:
We write 5 as the sum of the square of two natural numbers:
5=1+4=1
2
+2
2
On the number line, take OA=2 units.
Draw BA=1 unit, perpendicular to OA. Join OB.
By Pythagoras theorem, OB=
5
Using a compass with centre O and radius OB, draw an arc which intersects the number line at the point C. Then, C corresponds to
5
.
Presentation of
10
on the number line:
We write 10 as the sun of the square of two natural numbers:
10=1+9=1
2
+3
2
On the number line, taken OA=3 units.
Draw BA=1 unit, perpendicular to OA, Join OB.
By Phythagoras theorem, OB=
10
Using a compass with centre O and radius OB, draw an arc which intersects the number line at the point C. Then, C corresponds to
10
.
Presentation of
17
on the number line:
We write 17 as the sum of the square of two natural numbers.
17=1+16=1
2
+4
2
On the number line, take OA=4 units.
Draw BA=1 units, perpendicular to OA. Join OB.
By Pythagoras theorem, OB=
17
Using a compass with centre O and radius OB, draw an arc which intersects the number line at the point C. Then, C corresponds to
17
.
