Question

locate √7 on lumber line​

Answer 1

Answer:

Let O be the origin on the line l.

Let A be on the line such that OA=1.

Draw AB perpendicular to OA at A such that AB=1. Then

OB² = OA² + AB² = 1² + 1² =2

With O as centre and OB as radius draw an arc cutting the line at C.

Then OC=OB= √2

Again draw CD prependicular to l such that CD=1. Then

0D² = OC² + CD² =2+1=3. Thus OD =3 √3

Draw an arc with O as centre and OD as radius to cut l in E. Then OE=OD= √3

Draw EF prependicular to l at E such that EF = 2 and join OF. Now

OF² = 0E³ + EF² = 3+4=7

Hence OF = √7 With O as centre and OF as radius, cut l at G.

Then OG = OF = √7

Thus G locate √7 on the line l.

hope it's help full