Locate √7 on number line,√9 on number line
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Answered by
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Answer:
Let O be the origin on the line l.
- Let A be on the line such that OA=1.
- Draw AB perpendicular to OA at A such that AB=1. Then.
- OB2=OA2+AB2=12+12=2 Thus OB=2 .
- Again draw CD prependicular to l such that CD=1. Then.
- OD2=OC2+CD2=2+1=3. Thus OD=3 .
- Hence OF=7 . With O as centre and OF as radius, cut l at G.
Answered by
1
Step-by-step explanation:
- Let O be the origin on the line l.
- Let A be on the line such that OA=1.
- Draw AB perpendicular to OA at A such that AB=1. Then.
- OB2=OA2+AB2=12+12=2 Thus OB=2 .
- Again draw CD prependicular to l such that CD=1. Then.
- OD2=OC2+CD2=2+1=3. Thus OD=3 .
- Hence OF=7 . With O as centre and OF as radius, cut l at G.
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