locate root 10
on the somber line
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To locate √10 on number line follow the steps. =) let 3cm = 1 unit
1)√10 = √3²+1²
2)draw a number line OC such that OA=AB=OC=1 unit
3)draw a perpendicular line from C of 1 unit [as √10 = √3²+1² ] and name the point as C
4) join O and C it will form a triangle
by pythagoras theorem
OC = √10
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now taking the radius of OC in compass draw an arc touching the number line and that point will be√10 .
Read more on Brainly.in - https://brainly.in/question/3199245#readmore
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