Locate root 11 on the number line ? Plzzzz ans it I will mark you brainlist1
Answers
Answered by
1
we can solve this by two methods
1. By using pyathagoraen theroem
2.By standard form
By pyathagoraen theroem
(AC)²=(BC)²+(AB)²
(3)²+(UNDEROOT 2)²
= ^11
By standard form
1.First draw a line AB of 11 cm and extend it to 1cm to c
2.From A to B biscet it to O
3.From A to C draw a semi circle
4.Now make a perpendicular on B To D
5.From D to E is ^11
Hope this will help you
1. By using pyathagoraen theroem
2.By standard form
By pyathagoraen theroem
(AC)²=(BC)²+(AB)²
(3)²+(UNDEROOT 2)²
= ^11
By standard form
1.First draw a line AB of 11 cm and extend it to 1cm to c
2.From A to B biscet it to O
3.From A to C draw a semi circle
4.Now make a perpendicular on B To D
5.From D to E is ^11
Hope this will help you
ashunivv148:
Thank you so much
Similar questions