Locate root 11 on the number line ? Plzzzz ans it I will mark you brainlist1
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we can solve this by two methods
1. By using pyathagoraen theroem
2.By standard form
By pyathagoraen theroem
(AC)²=(BC)²+(AB)²
(3)²+(UNDEROOT 2)²
= ^11
By standard form
1.First draw a line AB of 11 cm and extend it to 1cm to c
2.From A to B biscet it to O
3.From A to C draw a semi circle
4.Now make a perpendicular on B To D
5.From D to E is ^11
Hope this will help you
1. By using pyathagoraen theroem
2.By standard form
By pyathagoraen theroem
(AC)²=(BC)²+(AB)²
(3)²+(UNDEROOT 2)²
= ^11
By standard form
1.First draw a line AB of 11 cm and extend it to 1cm to c
2.From A to B biscet it to O
3.From A to C draw a semi circle
4.Now make a perpendicular on B To D
5.From D to E is ^11
Hope this will help you
ashunivv148:
Thank you so much
mark it as brainlist
Listen plz i need ur help I have posted a question of English plz aswer it if you know. no one is answering it plz plz help I have very little time plz help
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