Question

locate root 17 and root 10 on single number line with steps

Answer 1

1)
$17 = \sqrt{16}^{2} + \sqrt{1} {}^{2}$
step-1 : in the real no. line take point A in any place and measure 4 units (4^2=16) and mark it as B

step-2: make a perpendicular on point B by the help of a rounder

step-3: in the perpendicular line made before measure 1 unit (1^2=1) and mark it C

step-4 : join the Point A and C

step-5: the required
hypotenuse is17^1/2

and for 10^1/2 also the same method is used but only the difference is the change of units .
take 3 units as base and 1 unit as perpendicular.
3^2=9 and 1^2 =1
9+1 =10
thus, 10^1/2 ={(3^1/2)^2 + (1^1/2)^2}^1/2

take the measurement of the both hypotenuse of both 17^1/2 and 10^1/2 and mark that measurement in the real no. line to locate it

Answer 2

Answer:

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