locate root 2 on number line
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) Initially mark a horizontal line, let it be number line. Mark a point O on it; then mark OA one unit on this line.
ii) At O erect a perpendicular to the number line; here again mark OB equals one unit.
iii) Join AB; with A as center and AB as radius mark cut off an arc on the number line at C.
So AC equals √2.
Proof:
Since by construction, OAB is a right triangle, with AB as hypotenuse.
Applying Pythagoras theorem, AB² = OA² + OB²
Each of OA & OB being one unit by construction.
AB² = 1 + 1 = 2
==> AB = √2 units.
Thus AC = √2 units.
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Answer:
- Firstly let's take a number line.
- Let 0 be O and 1 be A. OA be the base.
- Let A - B be the height with 1 unit.
- AB perpendicular to AO.
- Let's join O and B.
Therefore, now both AB, OB are equal to 1 unit.
Now using Pythagorean theorem:
⇢ OB² = OA² + AB²
⇢ 1² + 1²
⇢ 2
Now, taking square roots on both the sides:
⇢ OB = √2
Now, here OB is equal to √2 but we need this √2 here on number line.
So, now it's time to take the geometric equipments.
- Take the vertex point on point O.
- Now cut an arc in OB on the number.
- The new point on the number like would be C.
- Taking the arc we can replace the measure of OB to OC on the number line.
Therefore, OC = √2.
- You can draw these measures using the above steps.
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