Question

Locate root 7
on the number line​

Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

Let O be the origin on the line l.  

Let A be on the line such that OA=1.  

Draw AB perpendicular to OA at A such that AB=1. Then  

OB^2 = OA^2 + AB^2 = 1^1 + 1^2 = 2 Thus OB=  √2

With O as centre and OB as radius draw an arc cutting the line at C.  

Then OC=OB=  √2

Again draw CD perpendicular to l such that CD=1. Then  

 OD^2 = OC^2 + CD^2 = 2 + 1 = 3 Thus OD =  √3

Draw an arc with O as centre and OD as radius to cut l in E. Then OE=OD=  √3

Draw EF perpendicular to l at E such that EF = 2 and join OF. Now

  OF^2 = OE^2 + EF^2 = 3 + 4 = 7

Hence OF=  √7. With O as centre and OF as radius, cut l at G.  

Then OG=OF=  √7

Thus G represents   √7 on the line l.