Question

locate square root 3 e on number line​

Answer 1

First draw a number line having points (at least) [0,3]. If we denote the point 0 as “O” and point 1 as “A” then OA will be equal to 1 unit. Then at point A draw a perpendicular of length AB=1 unit ( equal to the distance from 0 to 1 in the number line i.e. OA). And join the points O and A, so that OAB is a right angled triangle. Then by pythagoras theorem,

First draw a number line having points (at least) [0,3]. If we denote the point 0 as “O” and point 1 as “A” then OA will be equal to 1 unit. Then at point A draw a perpendicular of length AB=1 unit ( equal to the distance from 0 to 1 in the number line i.e. OA). And join the points O and A, so that OAB is a right angled triangle. Then by pythagoras theorem,OB^2=OA^2+AB^2

First draw a number line having points (at least) [0,3]. If we denote the point 0 as “O” and point 1 as “A” then OA will be equal to 1 unit. Then at point A draw a perpendicular of length AB=1 unit ( equal to the distance from 0 to 1 in the number line i.e. OA). And join the points O and A, so that OAB is a right angled triangle. Then by pythagoras theorem,OB^2=OA^2+AB^2=> OB=sqrt (1^2+1^2)

First draw a number line having points (at least) [0,3]. If we denote the point 0 as “O” and point 1 as “A” then OA will be equal to 1 unit. Then at point A draw a perpendicular of length AB=1 unit ( equal to the distance from 0 to 1 in the number line i.e. OA). And join the points O and A, so that OAB is a right angled triangle. Then by pythagoras theorem,OB^2=OA^2+AB^2=> OB=sqrt (1^2+1^2)=>OB = root2

First draw a number line having points (at least) [0,3]. If we denote the point 0 as “O” and point 1 as “A” then OA will be equal to 1 unit. Then at point A draw a perpendicular of length AB=1 unit ( equal to the distance from 0 to 1 in the number line i.e. OA). And join the points O and A, so that OAB is a right angled triangle. Then by pythagoras theorem,OB^2=OA^2+AB^2=> OB=sqrt (1^2+1^2)=>OB = root2Now, again draw a perpendicular at point B of length BC= 1 unit and join the points O and C. Again by pythagoras theorem we get OC = root 3. Then by compus taking radius =OC, draw an arc so that it cuts the number line at D. Then the distance OD will be the square root of 3.

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