Question

Locate
$\sqrt{2}$
on the number line.​

Answer 1

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Answer 2

Answer:

Square root of 2

Step-by-step explanation:

Steps;-

⇒ Draw a number line and mark the center point as zero.

⇒ With same length as between 0 and 1, draw a line perpendicular to point (1), such that new line has a length of 1 unit.

⇒ Now join the point (0) and the end of new line of unity length.

⇒ A right angled triangle is constructed.  

⇒ Now let us name the triangle as ABC such that AB is the height (perpendicular), BC is the base of triangle and AC is the hypotenuse of the right angled triangle ABC.

⇒ Now length of hypotenuse, i.e., AC can be found by applying pythagoras theorem to the triangle ABC.

$AC^{2} = AB^{2} + BC^{2}$

        =  $1^{2} + 1^{2}$

        = 1 + 1

        = 2

AC = $\sqrt{2}$