Locate the centre of mass of 3 particles of mass m1=1kg,m2=2kg,M3=3kg at the corners of an equilateral triangle of each side 1m?
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m1=1kg
m2=2kg
m3=3kg
Xcm=1/4
Ycm=0.86
m2=2kg
m3=3kg
Xcm=1/4
Ycm=0.86
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Mubassera:
x2=1 m and y2=0 m. The answer is (7/12,under root 3/4)
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hope u understant
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