Question

Locate the centre of mass of a system of bodies of masses m1= 1 kg, m2 = 2 kg and m3 = 3 kg situated at the corners of an equilateral triangle of side 1 m.

Answer 1

by formula
M= m1+m2+m3

X= (m1x1+m2x2+m3x3)/M

Y = (m1y1+m2y2+m3y3)/M

find X and Y

that will be your answer C (X,Y)

Answer 2

Answer:

hope it helps u

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