Question

locate the centre of mass of an equilateral triangle having masses 1 ,2 ,3 gram and 1 metre aside​

Answer 1

The x coordinate of point B is 2/1 = 1 and  

From figure we get that sin 60 ° = BX / OB  

i.e. BX = √3 / 2 × 2 =1.732

The X and Y coordinates of point O, A, and B forming the equilateral triangle are respectively (0,0), (2,0), and (1,1.732). Let the masses 100g, 150g, and 200g be located at O,A and B respectively.Then,

   

                   (Here we will replace 1.732 by)

Thus the coordinate for centre of mass is