Question

Locate the centroid of a right angle triangle having base 100mm and height 150mm​

Answer 1

Answer:

Construction: Draw PG and QG parallel to BC and AB respectively.

By the basic proportionality theorem, we have, APPB=AGGD.

By the property of the centroid, we know that AGGD=21.

⇒APPB=2⇒AP=2PB⇒PB=13AB.

By the basic proportionality theorem, we have, CQQB=CGGF.

By the property of the centroid, we know that CGGF=21.

⇒CQQB=2⇒CQ=2QB⇒QB=13CB.

In this particular problem, it is given that AB=150 mm and BC=100 mm.

⇒BP=50 mm and BQ=1003 mm.

⇒ If B is the origin and BC and BA are the directions of the positive X axis and the positive Y axis respectively, the position of the centroid is (50,1003).

Step-by-step explanation:

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