Question

Locate the image formed by refraction in the situation shown in figure.
Figure

Answer 1

Answer:

DEAR NOT ABLE TO SEE THE FIGURE

PLEASE SEE IF YOU HAVE ATTACHED THE FIGURE WITH YOU QUESTION

Answer 2

The image formed by refraction is - 100.

Explanation:

Given data in the question :

When a beam of light goes over from one transparent medium to another, Crossing the screen it bends, separating the two outlets. This is called the refraction .

The  refractive indicex  are    

$\mu_{1}=1$  

$\mu_{2}=1.5$

$\mathrm{R}=20 \mathrm{cm}$ ⇒ Curvature Radius

$u=-25 \mathrm{cm}$

$\frac{\mu_{2}}{v}-\frac{\mu_{1}}{u}=\frac{\mu_{2}-\mu_{1}}{R}$

Put the values in above equation

$\frac{1.5}{v}=\frac{0.5}{20}-\frac{1}{25}$

$\frac{1.5}{v}=\frac{5}{200}-\frac{1}{25}$

$\frac{1.5}{v}=\frac{1}{40}-\frac{1}{25}$

$\frac{1.5}{v}=0.025-00.4$

$\frac{1.5}{v}=-0.015$

$v=-\frac{1.5}{0.015}$

v = - 100

So, the image on the side of S is 100 cm from the surface of (P).