Physics, asked by vijayakhotare, 4 months ago

Locate the position of image of the point O formed by concave refractive surface of radius of curvature 25cm the object is kept at 40cm in the front of the sphere and refractive index of spere.​

Answers

Answered by sharma1009pooja
1

Answer:

Given object distance u=40 cm, radius of curvature R=20 cm

refractive index n

2

=1.5 and n

1

=1

Now making use of the relation

v

n

2

u

n

1

=

R

n

2

−n

1

v

n

2

= Rn 2 −n 1 + un 1vn 2

= −201.5−1

− −401

v

n

2

=

−40

2

v=1.5×−20=−30

Answered by MAULIKSARASWAT
0

Answer: Bro may be this helps.....................

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