Locate the position of image of the point O formed by concave refractive surface of radius of curvature 25cm the object is kept at 40cm in the front of the sphere and refractive index of spere.
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1
Answer:
Given object distance u=40 cm, radius of curvature R=20 cm
refractive index n
2
=1.5 and n
1
=1
Now making use of the relation
v
n
2
−
u
n
1
=
R
n
2
−n
1
v
n
2
= Rn 2 −n 1 + un 1vn 2
= −201.5−1
− −401
v
n
2
=
−40
2
v=1.5×−20=−30
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