Question

location of B is north of A and location of C is east of A.the distance AB and AC are 5 kilometre and 12 kilometre respectively the shortest distance between the locations B and C is​

Answer 1

Here by Pythagoras theorem

(BC)^2=(AB)^2+(AC)^2

BC^2=5^2+12^2

BC^2=25+144

BC^2=169

BC=13

So,the shortest distance between B and C is 13km.

Answer 2

Answer:

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