locus formula..............
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Therefore, the equation to the locus under the given conditions is x2 + y2 = 16. Last one. In this one, we were to find out the locus of a point such that it is equidistant from two fixed points, which was the perpendicular bisector of the line joining the points. \sqrt{(x-1)^2+(y-1)^2}=\sqrt{(x-2)^2+(y-4)^2}.
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Sorry dear I can't understand the question
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