Locus of midpoints of chords of hyperbola 14. 9x² 25y² = 225, such that tangents at extrimities of these chords intersect at right
angle, is
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Step-by-step explanation:
Let (x
1
,y
1
) be the point of intersection of perpendicular tangents so that (x
1
,y
1
) lies on director circle ∴x
1
2
+y
1
2
=a
2
+b
2
...(1)
Then the chord will be chord of contact of (x
1
,y
1
)
∴
a
2
xx
1
+
b
2
yy
1
=1...(2)
If its mid-point is (h,k), then its equation is
a
2
hx
+
b
2
ky
=
a
2
h
2
+
b
2
k
2
...(3)
Compare (2) and (3) and find x
1
,y
1
and put in (1)
∴ Locus of (h,k) is (
a
2
x
2
+
b
2
y
2
)
2
(a
2
+b
2
)=x
2
+y
2
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