locus of P such
A(16) & B (3,5). Find equartion of locus of P such
that angleAPB is that right angled.
Answers
Answered by
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Answer:
16×3=48
16×5=80
48-80=48
then the p is 48
Answered by
0
Answer:
x² + y² - 4x - 11y + 28 = 0
Step-by-step explanation:
P = x,y
A = 1,6
B = 3,5
APB = 90°
which implies it is a right angled triangle having a right angle at P
PA² + PB² = AB²
(x - 1)² + (y - 6)² + (x - 3)² + (y - 5)² = (1-3)² + (6-5)²
after solving you will get,
2x² + 2y² - 8x - 22y + 61 = 5
2x² + 2y² - 8x - 22y + 56 = 0
divide 2 on both sides
x² + y² - 4x - 11y + 28 = 0
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