Question

locus of point equidistant from A point form
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Answer 1

Answer:

Let the point be P(x,y)

Then

(x−(a+b))

2

+(y−(a−b))

2

=

(x−(a−b))

2

+(y−(a+b))

2

(x−(a+b))

2

+(y−(a−b))

2

=(x−(a−b))

2

+(y−(a+b))

2

(x−(a+b))

2

−(x−(a−b))

2

=(y−(a+b))

2

−(y−(a−b))

2

(2x−2a)(a−b−(a+b))=(2y−2a)(a−b−(a+b))

2(x−a)(−2b)=2(y−a)(−2b)

x−a=y−a

or

x−y=0 is the required equation.

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