Question

Locus of the points of intersection of perpendicular tangents drawn one to each of the circles
x2 + y - 42 + 6y - 37 = 0, x2 + y2 - 4x + 6y - 20 = 0 is
1) 2 & 7 – 4x+6y=0
2) x2 + y2 - 4x + 6y - 50 = 0
3) x2 & 7 – bis + by-57=0
4) x2 + y2 - 4x + 6y - 70 = 0​

Answer 1

Answer:

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Step-by-step explanation:

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