Question

lodine atom
In the presence of samarium iodide, the aldehydes and ketones are reduced​

Answer 1

In the presence of a proton source, however, the dimer may undergo either disproportionation to form a samarium alkoxide and carbonyl compound, or protonation to form a carbinol radical ii followed by a second reduction and protonation, yielding an alcohol.

Answer 2

Answer:

lodine atom

In the presence of samarium iodide, the aldehydes and ketones are reduced

Explanation:

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