Math, asked by SunayMutya, 5 months ago

log 0.125 to the base 2

Answers

Answered by AdaDeiLoosu

Answer:

log

log 2

log 2 0.125=

log 2 0.125= log2

log 2 0.125= log2log0.125

log 2 0.125= log2log0.125 ....(log

log 2 0.125= log2log0.125 ....(log b

log 2 0.125= log2log0.125 ....(log b a=

log 2 0.125= log2log0.125 ....(log b a= logb

log 2 0.125= log2log0.125 ....(log b a= logbloga

log 2 0.125= log2log0.125 ....(log b a= logbloga )

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log 8

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log 81

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log 81 =

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log 81 = log2

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log 81 = log2log2

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log 81 = log2log2 −3

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log 81 = log2log2 −3 =−3 ...(loga

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log 81 = log2log2 −3 =−3 ...(loga b

log 2 0.125= log2log0.125 ....(log b a= logbloga )∴ log2log 81 = log2log2 −3 =−3 ...(loga b =bloga)

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