Question

log 0.5 to the base 32​

Answer 1

let

$log_{32}(0.5) = x$

this implies,

$(32) {}^{x} = 0.5$

$(2) {}^{5x} = (2) {}^{ - 1}$

then ,

$5x = - 1$

$x = \frac{ - 1}{5}$

I hope it help you ❤️