log 0.5 (x^2-5x+6)>-1
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Answered by
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Answered by
0
Answer:
- X€ [1,4]
- Step-by-step explanation:
- Step-by-step explanation:X>0
- Step-by-step explanation:X>0base <1
- Step-by-step explanation:X>0base <1X2 -5x+6<(0.5)-1
- Step-by-step explanation:X>0base <1X2 -5x+6<(0.5)-10.5^1
- Step-by-step explanation:X>0base <1X2 -5x+6<(0.5)-10.5^1X2 -5x+6<2
- Step-by-step explanation:X>0base <1X2 -5x+6<(0.5)-10.5^1X2 -5x+6<26-2=4
- Step-by-step explanation:X>0base <1X2 -5x+6<(0.5)-10.5^1X2 -5x+6<26-2=44X2 -5+4<0
- Step-by-step explanation:X>0base <1X2 -5x+6<(0.5)-10.5^1X2 -5x+6<26-2=44X2 -5+4<0( X-1 ) ( X -4)
- Step-by-step explanation:X>0base <1X2 -5x+6<(0.5)-10.5^1X2 -5x+6<26-2=44X2 -5+4<0( X-1 ) ( X -4) X€ [ 1,4 ]
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