Math, asked by omarhassanomardeeq, 9 months ago

log 0.9=log 9÷10=log9_log10
log3²-log10 2log3-log10 2(0.301)-1=0.602-1=-0.398=0.4​

Answers

Answered by tusharjsr313
0

Step-by-step explanation:

Basic Log Rules

When the argument of a logarithm is the product of two numerals, the logarithm can be re-written as the addition of the logarithm of each of the numerals.

logb(x × y) = logbx + logby

EX: log(1 × 10) = log(1) + log(10) = 0 + 1 = 1

When the argument of a logarithm is a fraction, the logarithm can be re-written as the subtraction of the logarithm of the numerator minus the logarithm of the denominator.

logb(x / y) = logbx - logby

EX: log(10 / 2) = log(10) - log(2) = 1 - 0.301 = 0.699

If there is an exponent in the argument of a logarithm, the exponent can be pulled out of the logarithm and multiplied.

logbxy = y × logbx

EX: log(26) = 6 × log(2) = 1.806

It is also possible to change the base of the logarithm using the following rule.

logb(x) =

logk(x)

logk(b)

EX: log10(x) =

log2(x)

log2(10)

To switch the base and argument, use the following rule.

logb(c) =

1

logc(b)

EX: log5(2) =

1

log2(5)

Other common logarithms to take note of include:

logb(1) = 0

logb(b) = 1

logb(0) = undefined

limx→0+logb(x) = - ∞

ln(ex) = x

Answered by sahitya17
0

Step-by-step explanation:

what should we find in this question ??

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