log 0.9=log 9÷10=log9_log10
log3²-log10 2log3-log10 2(0.301)-1=0.602-1=-0.398=0.4
Answers
Step-by-step explanation:
Basic Log Rules
When the argument of a logarithm is the product of two numerals, the logarithm can be re-written as the addition of the logarithm of each of the numerals.
logb(x × y) = logbx + logby
EX: log(1 × 10) = log(1) + log(10) = 0 + 1 = 1
When the argument of a logarithm is a fraction, the logarithm can be re-written as the subtraction of the logarithm of the numerator minus the logarithm of the denominator.
logb(x / y) = logbx - logby
EX: log(10 / 2) = log(10) - log(2) = 1 - 0.301 = 0.699
If there is an exponent in the argument of a logarithm, the exponent can be pulled out of the logarithm and multiplied.
logbxy = y × logbx
EX: log(26) = 6 × log(2) = 1.806
It is also possible to change the base of the logarithm using the following rule.
logb(x) =
logk(x)
logk(b)
EX: log10(x) =
log2(x)
log2(10)
To switch the base and argument, use the following rule.
logb(c) =
1
logc(b)
EX: log5(2) =
1
log2(5)
Other common logarithms to take note of include:
logb(1) = 0
logb(b) = 1
logb(0) = undefined
limx→0+logb(x) = - ∞
ln(ex) = x
Step-by-step explanation:
what should we find in this question ??