log 0 value with reason
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The answer is. -infinity
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`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
`log 0 = x` can be rewritten as `10^x = 0`. Since no value of x solves this equation, the expression log(0) is undefined.
However, notice that `10^x` gets pretty close to zero if you use large negative values for x. In fact, you can get `10^x` to be as close to zero as you desire if you choose a low enough x value. For this reason we can say `lim_(x->0+) log x = -infty`
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