Question

log^ 1 ( 0 + 1/3 * log(3 ^ (2sqrt(x)) + 271) = 2 .​

Answer 1

Answer:

128√2

Step-by-step explanation:

x=3+2

2 1)

=>1/x=1/(3+2√2)

=>1/x=(3-2√2)/( (3+2√2)*(3-2√2) )

[ dividing and multiplying R.H.S. by (3-2√2)

=1/x=(3-2√2)/(9-8)=3-2√2

Now x-1/x=(3+2√2)-(=3-2√2)

=(-4√2)

=-128√2.